python实现的登录和操作开心网脚本分享

SNS什么的我是一直无爱的，这次蛋疼写了个登录开心网(kaixin001)并向所有好友发送站内消息的脚本。

开心网在登录的时候做了一些处理，并不传原始密码，从js分析到的结果是：登录时会生成一个随机的key，然后用这个key和原始密码进行xxtea加密，把加密后的结果再进行sha1加密。之后post这个key以及加密后的密码进行登录验证。

以下是很简陋的脚本内容：

#coding: utf-8
"""
开心网操作脚本

Author: piglei2007@gmail.com
Version: 1.0
"""
import re
import urllib
import urllib2
import random
import hashlib
import binascii
import cookielib
import simplejson

from xxtea import encrypt

LOGIN_URL = "http://www.kaixin001.com/login/login_api.php"
LOGIN_KEY_URL = "http://www.kaixin001.com/"
FRIEND_LIST_URL = "http://www.kaixin001.com/interface/suggestfriend.php"
MESSAGE_SEND_URL = "http://www.kaixin001.com/msg/post.php"

LOGIN_KEY_RE = re.compile(r"new\sEnLogin\('(.*?)'")

class LoginError(Exception):
  """
  登录失败抛出异常
  """

class Kaixin001User(object):
  """
  操作kaixin001，现有方法：

    get_login_key － 获得用户访问登录页面时分配的加密key

    get_rpassword － 获得经过xxtea以及sha1加密后的密码

    login - 登录

    get_friends_list - 获得所有好友，返回字典格式

    send_messages_to_all － 给所有好友发消息
  """

  def __init__(self, username, password):
    self.username = username
    self.password = password
    self.cj = cookielib.CookieJar()
    opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(self.cj))
    opener.addheaders = [
      ("User-agent", "Mozilla/5.0 (X11; U; FreeBSD i386; en-US; rv:1.9.1) Gecko/20090704 Firefox/3.5"),
      ("Accept", "*/*"),
      ("Host", "www.kaixin001.com")
    ]
    urllib2.install_opener(opener)

  def get_login_key(self):
    """
    获得登录时候的加密key
    """
    _temp = urllib2.urlopen(LOGIN_KEY_URL).read()
    key = LOGIN_KEY_RE.search(_temp).group(1)
    return key

  def login(self):
    """
    登录
    """
    login_key = self.get_login_key()
    rpassword = self.get_rpassword(self.password, login_key)
    login_params = {
      'email': self.username,
      'encypt': login_key,
      'rpasswd': rpassword,
      'url': '/home/',
      'ver': '1'
    }
    req = urllib2.Request(LOGIN_URL, urllib.urlencode(login_params), {
      "Referer": "http://www.kaixin001.com/"
    })
    result = urllib2.urlopen(req).read()

    # 登录失败
    if "errno" in result:
      raise LoginError("登录失败，请检查用户名或密码")

    print "用户 %s 登录成功！" % self.username

    return 'ok'

  def get_friends_list(self):
    """
    获得所有好友列表
    """
    get_friends_params = {
      't': str(random.random()),
      'type': 'all',
    }
    result = urllib2.urlopen(FRIEND_LIST_URL, urllib.urlencode(get_friends_params)).read()
    friends = simplejson.loads(result)

    print "你一共有 %s 位好友" % (len(friends) - 1)
    return friends

  def send_messages_to_all(self, message=''):
    """
    给所有好友发消息
    """
    friends = self.get_friends_list()
    send_params = {
      'attachment_cancel': '',
      'attachment_forwarding': '',
      'attachment_random': '',
      'code': '',
      'content': message,
      'forward_thread': '',
      'rcode': '',
      'service': '0',
      'texttype': 'html',
      'uids': ",".join([str(f['uid']) for f in friends])
    }
    result = urllib2.urlopen(MESSAGE_SEND_URL, urllib.urlencode(send_params))
    print result.geturl()
    print "消息发送成功"
    return 'ok'

  def get_rpassword(self, password, key):
    """
    获得加密后的密码
    """
    xxtea_pw = binascii.b2a_hex( encrypt(password, key) )
    r_password = hashlib.sha1(xxtea_pw).hexdigest()
    return r_password

if __name__ == '__main__':
  kxu = Kaixin001User(
    username = 'your_username',
    password = 'your_password'
  )
  kxu.login()
  kxu.send_messages_to_all("This message is send by Python.")

这是脚本中需要用到的xxtea算法的python实现（xxtea.py）：

import struct

_DELTA = 0x9E3779B9 

def _long2str(v, w):
  n = (len(v) - 1) << 2
  if w:
    m = v[-1]
    if (m < n - 3) or (m > n): return ''
    n = m
  s = struct.pack('<%iL' % len(v), *v)
  return s[0:n] if w else s 

def _str2long(s, w):
  n = len(s)
  m = (4 - (n & 3) & 3) + n
  s = s.ljust(m, "\0")
  v = list(struct.unpack('<%iL' % (m >> 2), s))
  if w: v.append(n)
  return v 

def encrypt(str, key):
  if str == '': return str
  v = _str2long(str, True)
  k = _str2long(key.ljust(16, "\0"), False)
  n = len(v) - 1
  z = v[n]
  y = v[0]
  sum = 0
  q = 6 + 52 // (n + 1)
  while q > 0:
    sum = (sum + _DELTA) & 0xffffffff
    e = sum >> 2 & 3
    for p in xrange(n):
      y = v[p + 1]
      v[p] = (v[p] + ((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4) ^ (sum ^ y) + (k[p & 3 ^ e] ^ z))) & 0xffffffff
      z = v[p]
    y = v[0]
    v[n] = (v[n] + ((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4) ^ (sum ^ y) + (k[n & 3 ^ e] ^ z))) & 0xffffffff
    z = v[n]
    q -= 1
  return _long2str(v, False) 

def decrypt(str, key):
  if str == '': return str
  v = _str2long(str, False)
  k = _str2long(key.ljust(16, "\0"), False)
  n = len(v) - 1
  z = v[n]
  y = v[0]
  q = 6 + 52 // (n + 1)
  sum = (q * _DELTA) & 0xffffffff
  while (sum != 0):
    e = sum >> 2 & 3
    for p in xrange(n, 0, -1):
      z = v[p - 1]
      v[p] = (v[p] - ((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4) ^ (sum ^ y) + (k[p & 3 ^ e] ^ z))) & 0xffffffff
      y = v[p]
    z = v[n]
    v[0] = (v[0] - ((z >> 5 ^ y << 2) + (y >> 3 ^ z << 4) ^ (sum ^ y) + (k[0 & 3 ^ e] ^ z))) & 0xffffffff
    y = v[0]
    sum = (sum - _DELTA) & 0xffffffff
  return _long2str(v, True) 

if __name__ == "__main__":
  print decrypt(encrypt('Hello XXTEA!', '16bytelongstring'), '16bytelongstring')